Hi class, this quiz was an easy one. it has to parts, so let us start with it.
- the first part we need to create a function called palindrome, this function will switch any character string and if it is the same we will call it palindrome
We have tu include #include <string> in order to work with strings, and the main part is a for
for( i= cadena.size()-1; i>=0; i–)
{
cadena_inv += cadena.at(i);}
here is it, the for is going to order the character switched and downstairs we will evaluate with an if to know if it was a palindrome or not
HERE IS THE CODE - The second part is easier. The user will enter a range of numbers and we just have tu add the ones wich are divisible by three.
Also is a for, but now we have an array, is like this
for(int i=0; i<cant; i=i+1)
{
if(numbers[i]%3==0){
n=n+numbers[i]; }
}
CODE
Quiz 05 by alibarramg is licensed under a Creative Commons Attribution-ShareAlike 4.0 International License.