#TC1017 #WSQ09

This programm was very straightforward, since the formula to calculate the factorial is very simple, the tricky part was making the factorial function recursive, because it has to call itself with evey iteration in order to obtain the previous value given to n. In fact, this was my first use of recursion in this semester, that makes it noteworthy I think!

Source code below: [GitHub link: https://github.com/diegodamy/WSQ09 ]

#include <iostream>
using namespace std;
int factorial (int n){
if (n == 0){
return 1;
} else {
return n*factorial(n-1);
}
}
int main(){
int number;
char decision;

do {
cout << “To calculate the factorial, please enter the integer number:” << endl;
cin >> number;

if (number <0){
cout << “Please enter only positive numbers.” << endl;
cin >> number;
} else {
cout << “The factorial of ” << number << ” is ” << factorial (number) << endl;
}

cout << endl << “Would you like to calculate the factorial of another number? Y/N:” << endl;
cin >> decision;
cout << endl;

} while (decision == ‘Y’);

if (decision !=’Y’){
cout << “Thank you. Goodbye!”;
}

}

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Photo Credit: <a href=”https://www.flickr.com/photos/49968232@N00/6267826523/”>Leo Reynolds</a> via <a href=”http://compfight.com”>Compfight</a&gt; <a href=”https://creativecommons.org/licenses/by-nc-sa/2.0/”>cc</a&gt;

#TC1017 #WSQ07

This problem was actually a little more difficult to solve than the previous ones. Although it does what it needs to do, I think I made things somewhat more complicated than they needed to be, which is why I added some comments to remind myself what I did and why.

The programm begins by asking the user for two numbers, for which it will calculate the total sum of the numbers inbetween, inclusive. First of all it checks that the numbers given are in the proper order: lower to higher, then I use the difference between those numbers to calculate the amount of sums that have to be done and add a -1 so the difference matches the quantity of numbers between them properly.

Once that has been done, the programm then sums the numbers n times using a while loop until the counter (n) matches the quantity of numbers between the ranges.

As I said, a little complicated but it works!

Source Code:

#include <iostream>
using namespace std;

int main(){

int lower, higher;
int difference, sum;
int counter;
int loweract;

cout <<“Please enter the lower bound:” << endl;
cin >> lower;
cout << “Please enter the higher bound:” << endl;
cin >> higher;

while (lower > higher) {

cout << endl;

cout << “Please correct the order of your bounds!” << endl;

cout <<“Please enter the lower bound:” << endl;
cin >> lower;
cout << “Please enter the higher bound:” << endl;
cin >> higher;

}

do { //could this be done with a for loop?

difference = ((higher – lower)-1); // gives the number of integer sums aside from the bounds
counter ++; // counter is needed so that the sum stops once the counter reaches the number of sums
loweract = lower + counter

Continue reading “Range between numbers” →

#TC1017 #WSQ08

For this programm I had to go back to WSQ03, which just did some basic operations with two numbers, and step it up a notch by implementing functions.

I really like the way functions work, it might be a little easy lo loose track of what the compiler is doing with all of those variables, but once you get the hang of it it becomes very interesting to see all the things you can doy by passing paramaters onto other functions and using their results for something else.

The only problem I had when programming this was, once again, checking syntax of the functions. Everything else was donde smoothly.

Source code:

#include <iostream>
using namespace std;
double primero, segundo;

double suma (double a, double b)
{
int resultado1 = (a+b);
cout << “El resultado de la suma es: ” << resultado1 << endl;
}

double resta1 (double a, double b)
{
double resultado2 = a-b;
cout << “La resta del primer numero menos el segundo es: ” << resultado2 << endl;
}

double resta2 (double a, double b)
{
double resultado3 = b-a;
cout << “La resta del segundo numero menos el primero es: ” << resultado3 << endl;
}
double producto (double a, double b)
{
double resultado4 = a*b;
cout << “El producto de ambos numeros es: ” << resultado4 << endl;
}

double division1 (double a, double b)
{
double resultado5 = a/b;
cout << “El resultado de el primer numero entre el segundo es: ” << resultado5 << endl;
}

double division2 (double a, double b)
{
double resultado6 = b/a;
cout << “El resultado del segundo numero entre el primero es: ” << resultado6 << endl;
}
int main() {
cout << “Ingrese el valor del primer numero :” << endl;
cin >>

Continue reading “Now with functions” →

#TC1017 #WSQ06

This time we had to create a simple game which basically generates a random number between 1 and 100 and it’s up to the user to try and guess what number the computer came up with. For this I created some if statements inside a do-while loop that keeps checking for an inequality between the random number and the user’s guess.

If the user doesn’t guess correctly, the programm checks whether the number guessed is inferior or superiror to the generated number, and thus informs the user. The code also keeps track of every guess and when guessed correctly displays the user how many tries he made.

This problem has been the most complex so far, since it requieres the implementation of some logic, but the tricky part was finding out how to generate a random number and keen the program running until the user guesses correctly.

I checked online how to generate a random number first, and it turned out you need to include some extra “files” into the code, as well as a specific function to generate te number and keep it between the given range.

For keeping the program running as along as the number isn’t guesses I asked Bauer for help and he instructed me to write an inequality as an argument for the while statement.

Once this was done all that was left was correcting the number of tires that were displayed to the user, since I didn’t count the very first try, so my programm was only showing one try. In the end, I decided to cheat a little and just add a +1 to the number os tries displayed. It works just fine 😛

Source code:

#include <iostream>
#include <cstdlib>
#include <ctime>

using namespace std;

int main (void){

srand (time(NULL)); //truly

Continue reading “Creating a game” →

#TC1017 #WSQ04

Flipped learning was a new concept for me when I started studying here at TEC, on the other hand, having been abroad in Germany for almost a year served me as my first experience as to what these “lectures” were really about.

I have to agree, they really kinda suck most of the time, as a friend of mine put it, it’s like trying to drink water from a fire hose. It’s just too much too fast I’d have to say; they’re unengaging, and mostly it doesn’t even make much sense to go to the lecture because you might as well just pick up the book and read it yourself, at your own pace, from the comfort of your house or with a study group. That’s why I have to agree with the blogs I read, altough as they said, not all of them are incredibly horrendous.

From time to time a teacher comes along with cool ideas to catch the students’ attention, the way he presents the topic can really help or damper a lecture, but sadly this is really the exeption.

Now here at TEC more and more of my classes are breaking the mold and trying to teach us in a different way. Sure, sometimes experimenting doesn’t work the first time, but at the end of the day it’s worth it. I mean it might not work because flipped learning requieres more imput from the student I think. You have to be interested in doing it, otherwise the class won’t go anywhere, whereas in a lecture it doesn’t even matter if you attend it or not. Sometimes it might not work because after all, we need some time to adjust to the new changes and don´t really know what´s expected from us, say in an

Continue reading “Reflections on flipped learning” →

#TC1017 #WSQ05

This program was a temperature converter and was finished in a couple of minutes, I think the previous programms really refreshed my memory as to what C++ was. The only problem was I could not recall the proper syntax for if statements and had to check the ebook to remember.

Below’s the proof and code as usual. I ran the program twice for each possible scenario (water boiling or not).

Source code:

#include <iostream>
using namespace std;

float fahr;

int main(){
cout <<“What’s the temperature in Fahrenheits?” << endl;
cin >> fahr;
cout << endl;
cout <<“The equivalent temperature in Celsius is “;
cout << 5*(fahr-32)/9;
cout <<” Degrees.” << endl;
cout << endl;

if (fahr >= 212 ) {
cout << “Water boils at this temperature under normal conditions” << endl;
} else {
cout << “Water does not boil at this temperature under normal conditions” << endl;
}
}

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