Warning: The magic method Slickr_Flickr_Plugin::__wakeup() must have public visibility in /home/kenbauer/public_kenscourses/tc101fall2015/wp-content/plugins/slickr-flickr/classes/class-plugin.php on line 152

Warning: Cannot modify header information - headers already sent by (output started at /home/kenbauer/public_kenscourses/tc101fall2015/wp-content/plugins/slickr-flickr/classes/class-plugin.php:152) in /home/kenbauer/public_kenscourses/tc101fall2015/wp-includes/feed-rss2.php on line 8
‘#WSQ13’ Articles at TC101 Fall 2015 https://kenscourses.com/tc101fall2015 Introduction to Programming Python and C++ Thu, 26 Nov 2015 05:46:32 +0000 en hourly 1 https://creativecommons.org/licenses/by/4.0/ WSQ13 – Babylonian Method https://kenscourses.com/tc101fall2015/2015/wsq13-babylonian-method-13/ Thu, 26 Nov 2015 05:46:32 +0000 http://finntec.wordpress.com/?p=119 Here you can find my code for WSQ13:

https://github.com/finntec/wsq13.git

]]>
https://creativecommons.org/licenses/by/4.0/
WSQ 13: Babylonian method https://kenscourses.com/tc101fall2015/2015/wsq-13-babylonian-method-2/ Thu, 26 Nov 2015 05:16:32 +0000 http://ivancortes96.wordpress.com/?p=154 It was easy after knowing how the babylonian method worked:

link to video that explains babylonian method:

link to my code:

https://github.com/cortesivan96/WSQs/blob/master/babylonian%20method%20(WSQ13)

]]>
https://creativecommons.org/licenses/by/4.0/
WSQ13 https://kenscourses.com/tc101fall2015/2015/wsq13-28/ Thu, 26 Nov 2015 03:40:22 +0000 http://giorgio6859.wordpress.com/?p=103 ]]> Para este WSQ vi un video en youtube sobre el método babilónico. Logré deducir casi todo con mi propia lógica pero en un momento llegué a atascarme. Por suerte estaba haciéndola durante mi clase de programación y Ken me dio un empujoncito que me ayudó a ingeniármelas. Aquí está el código.

//Babylonian Method
#include <iostream>
using namespace std;

float bab(int a){
float x=a;
float y=1;
int i=0;
while(i<20){
x=(x+y)/2;
y=a/x;
i=i+1;}
return x;}
int main(){
cout<<“Dame el número para sacarle su raíz cuadrada “<<endl;
int a;
cin>>a;
cout<<“La raíz cuadrada de “<<a<<” es “<<bab(a)<<endl;
return 0;}

]]>
https://creativecommons.org/licenses/by/4.0/
WSQ13 https://kenscourses.com/tc101fall2015/2015/wsq13-26/ Thu, 26 Nov 2015 01:23:05 +0000 http://ilkapython.wordpress.com/?p=147 WSQ13

]]>
https://creativecommons.org/licenses/by/4.0/
WSQ13 https://kenscourses.com/tc101fall2015/2015/wsq13-27/ Thu, 26 Nov 2015 01:22:10 +0000 http://5nbppkkyj.wordpress.com/?p=157 ]]> I wrote a program that calculates the square root of a number using the Babylonian method. A function baby receives any number and returns a float.

https://github.com/DianaJU/Write/blob/master/baby.py

]]>
https://creativecommons.org/licenses/by/4.0/
WSQ13 – Babylonian Method https://kenscourses.com/tc101fall2015/2015/wsq13-babylonian-method-12/ Wed, 25 Nov 2015 23:48:33 +0000 http://dragv.wordpress.com/?p=187 ]]> Short and simple.

Here’s my code:

https://github.com/Dragv/wsq13/tree/master

]]>
https://creativecommons.org/licenses/by/4.0/
WSQ13 https://kenscourses.com/tc101fall2015/2015/wsq13-25/ Wed, 25 Nov 2015 23:45:44 +0000 http://alansprogramming.wordpress.com/?p=262 GitHub code link

]]>
https://creativecommons.org/licenses/by/4.0/
WSQ13 https://kenscourses.com/tc101fall2015/2015/wsq13-24/ Wed, 25 Nov 2015 23:28:55 +0000 http://fernyalanis.wordpress.com/?p=124 Here is my code 😀

https://github.com/FernyAlanis/wsq11-17/blob/master/WSQ13

]]>
https://creativecommons.org/licenses/by/4.0/
#WSQ13 https://kenscourses.com/tc101fall2015/2015/wsq13-23/ Wed, 25 Nov 2015 22:29:43 +0000 http://brayangcblog.wordpress.com/?p=150 ]]> 17588975470_df1a727758_z

Foto: https://flic.kr/p/sNh6BL

Este WSQ estuvo fácil, solo tuve que ver de que trataba el método  y lo pude hacer. Aqui esta el link de mi código:

https://github.com/BrayanGc/Codigos/blob/master/BaMe.cpp

]]>
https://creativecommons.org/licenses/by/4.0/
#WSQ13 https://kenscourses.com/tc101fall2015/2015/wsq13-21/ Wed, 25 Nov 2015 21:37:19 +0000 http://alan46bc.wordpress.com/?p=79 ]]> #include <iostream>
using namespace std;

float raiz (float a){
float x = a / 2;
for (int i=0; i <20; i++){
x = .5*(x+(a/x));
}
return x;
}

int main (){
float a, r;
cout << “Escribe un numero al que quieras sacarle su raiz cuadrada “;
cin >> a;
float s = raiz (a);
cout << “la raiz cuadrada de  ” << a << ” = “<< s << endl;
return 0;
}screen3

This one was a bit hard but I research some information on the internet and I could make it.

]]>
https://creativecommons.org/licenses/by/4.0/