question 1:<\/strong><\/p>\n #include<\/a> <iostream><\/p>\n #include<\/a> <vector><\/p>\n using namespace std;<\/p>\n <\/p>\n int findThrees(vector<int>list){<\/p>\n int modulo;<\/p>\n int suma=0;<\/p>\n int num=0;<\/p>\n <\/p>\n do{<\/p>\n modulo=list[num]%3;<\/p>\n if(modulo==0){<\/p>\n suma=list[num]+suma;<\/p>\n }<\/p>\n num++;<\/p>\n } while(num< list.size());<\/p>\n <\/p>\n return suma;<\/p>\n }<\/p>\n <\/p>\n int main() {<\/p>\n vector<int>list;<\/p>\n int tam;<\/p>\n int num;<\/p>\n <\/p>\n cout<<“Dame una lista de numeros y solo sumare los numeros que sean divisibles entre 3.”<<endl;<\/p>\n cout<<“Dame la cantidad de datos que tendra tu lista: “;<\/p>\n cin>>tam;<\/p>\n <\/p>\n for (int n=0; n<tam; n++){<\/p>\n cout<<“Dame un numero: “;<\/p>\n cin>>num;<\/p>\n list.push_back(num);<\/p>\n }<\/p>\n cout<<“La suma es: “<<findThrees(list)<<endl;<\/p>\n return 0;<\/p>\n }<\/p>\n <\/p>\n Question 2:<\/strong><\/p>\n <\/p>\n #include<\/a> <iostream><\/p>\n #include<\/a> <vector><\/p>\n using namespace std;<\/p>\n <\/p>\n int dotProduct(vector<int>v1, vector<int>v2){<\/p>\n int multi=0;<\/p>\n <\/p>\n for (int n=0; n<v1.size(); n++)<\/p>\n {<\/p>\n multi=v1[n]*v2[n]+multi;<\/p>\n }<\/p>\n <\/p>\n return multi;<\/p>\n }<\/p>\n <\/p>\n int main(){<\/p>\n vector<int>v1;<\/p>\n vector<int>v2;<\/p>\n int tam;<\/p>\n int num;<\/p>\n int tam2;<\/p>\n int num2;<\/p>\n <\/p>\n cout<<“Dame la cantidad de valores de la primer lista:(ambas listas deben tener el mismo tamano)”<<endl;<\/p>\n cin>>tam;<\/p>\n for(int n=0;n<tam;n++){<\/p>\n cout<<“Dame un numero”<<endl;<\/p>\n cin>>num;<\/p>\n v1.push_back(num);<\/p>\n }<\/p>\n <\/p>\n cout<<“Dame la cantidad de valores de la segunda lista:(ambas listas deben tener el mismo tamano) “<<endl;<\/p>\n cin>>tam2;<\/p>\n for(int n=0;n<tam;n++){<\/p>\n cout<<“Dame un numero”<<endl;<\/p>\n cin>>num2;<\/p>\n v2.push_back(num);<\/p>\n }<\/p>\n <\/p>\n if (tam != tam2)<\/p>\n {<\/p>\n cout << “Error:” << endl;<\/p>\n cout << “-1” << endl;<\/p>\n }<\/p>\n else<\/p>\n {<\/p>\n cout<<“El resultado es : “<<dotProduct(v1,v2)<<endl;<\/p>\n }<\/p>\n return 0;<\/p>\n }<\/p>\n <\/p>\n<\/div>\n","protected":false},"excerpt":{"rendered":" question 1:#include <iostream>#include <vector>using namespace std; int findThrees(vector<int>list){int modulo;int suma=0;int num=0; do{modulo=list[num]%3;if(modulo==0){ suma=list[num]+suma;  … Continue reading