{"id":34833,"date":"2016-04-04T23:57:13","date_gmt":"2016-04-05T04:57:13","guid":{"rendered":"http:\/\/valevazquezruizblog.wordpress.com\/?p=257"},"modified":"2016-04-05T00:29:40","modified_gmt":"2016-04-05T05:29:40","slug":"quiz6-euclide-algorythm","status":"publish","type":"post","link":"https:\/\/kenscourses.com\/tc101winter2016\/2016\/04\/quiz6-euclide-algorythm\/","title":{"rendered":"QUIZ#6, Euclide algorythm"},"content":{"rendered":"<figure data-shortcode=\"caption\" id=\"attachment_259\" style=\"width: 829px\" class=\"wp-caption alignnone\"><img decoding=\"async\" class=\"alignnone size-full wp-image-259\" src=\"http:\/\/kenscourses.com\/tc101winter2016\/wp-content\/uploads\/2016\/04\/34cccb93c391a2478ded656e2abfe838.jpg\" alt=\"quiz6\"   \/><figcaption class=\"wp-caption-text\">Resumiendo las instrucciones, deber\u00edamos crear un c\u00f3digo que recibe dos n\u00fameros o par\u00e1metros por parte del usuario, a continuaci\u00f3n, en una funci\u00f3n se va a imprimir el mayor denominador que divide a ambos n\u00fameros.<\/figcaption><\/figure>\n<p><img decoding=\"async\" class=\"alignnone size-full wp-image-262\" src=\"http:\/\/kenscourses.com\/tc101winter2016\/wp-content\/uploads\/2016\/04\/aa365867c442785cda79f63817558227.jpg\" alt=\"quiz6compile\"   \/><\/p>\n<p>C\u00d3DIGO:<\/p>\n<p>&nbsp;<\/p>\n<p>#include &lt;iostream&gt;<\/p>\n<p>using namespace std;<\/p>\n<p>&nbsp;<\/p>\n<p>int euclidianAlgo(int first, int second){<\/p>\n<p>int tem=0;<\/p>\n<p>int res=first%second;<\/p>\n<p>while(res!=0){<\/p>\n<p>first=second;<\/p>\n<p>second=res;<\/p>\n<p>res=first%second; }<\/p>\n<p>&nbsp;<\/p>\n<p>return second; }<\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p>int main() {<\/p>\n<p>int first, second, val;<\/p>\n<p>cout&lt;&lt;&#8220;This program does the Euclidian Algorithm of the range of numbers you give&#8221;&lt;&lt;endl;<\/p>\n<p>cout&lt;&lt;&#8220;Type the lower value&#8221;&lt;&lt;endl;<\/p>\n<p>cin&gt;&gt;first;<\/p>\n<p>cout&lt;&lt;&#8220;Ok now type the higher value&#8221;&lt;&lt;endl;<\/p>\n<p>cin&gt;&gt;second;<\/p>\n<p>val=euclidianAlgo(first, second);<\/p>\n<p>cout&lt;&lt;&#8220;The greatest denominator of the two numbers is: &#8220;&lt;&lt;&#8221; &#8220;&lt;&lt;val&lt;&lt;endl; }<\/p>\n<p>  <a rel=\"nofollow\" href=\"http:\/\/feeds.wordpress.com\/1.0\/gocomments\/valevazquezruizblog.wordpress.com\/257\/\"><img decoding=\"async\" alt=\"\" border=\"0\" src=\"http:\/\/kenscourses.com\/tc101winter2016\/wp-content\/uploads\/2016\/04\/b735d5c1dff85f959f73bee369fe5421.jpg\" \/><\/a> <img loading=\"lazy\" decoding=\"async\" alt=\"\" border=\"0\" src=\"http:\/\/kenscourses.com\/tc101winter2016\/wp-content\/uploads\/2016\/04\/a846123181949ae9eca56eb04f8c8766.jpg#038;blog=105357572&#038;%23038;post=257&#038;%23038;subd=valevazquezruizblog&#038;%23038;ref=&#038;%23038;feed=1\" width=\"1\" height=\"1\" \/><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Resumiendo las instrucciones, deber\u00edamos crear un c\u00f3digo que recibe dos n\u00fameros o par\u00e1metros por parte del usuario, a continuaci\u00f3n, en una funci\u00f3n se va a imprimir el mayor denominador que divide a ambos n\u00fameros. C\u00d3DIGO: &nbsp; #include &lt;iostream&gt; using namespace std; &nbsp; int euclidianAlgo(int first, int second){ int tem=0; int res=first%second; while(res!=0){ first=second; second=res; res=first%second; &hellip; <a href=\"https:\/\/kenscourses.com\/tc101winter2016\/2016\/04\/quiz6-euclide-algorythm\/\" class=\"more-link\">Continue reading <span class=\"screen-reader-text\">QUIZ#6, Euclide algorythm<\/span><\/a><\/p>\n","protected":false},"author":41,"featured_media":34864,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[5,4],"tags":[223,45],"class_list":["post-34833","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-blogs","category-syndicated","tag-quiz6","tag-sin-categoria"],"_links":{"self":[{"href":"https:\/\/kenscourses.com\/tc101winter2016\/wp-json\/wp\/v2\/posts\/34833","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/kenscourses.com\/tc101winter2016\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/kenscourses.com\/tc101winter2016\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/kenscourses.com\/tc101winter2016\/wp-json\/wp\/v2\/users\/41"}],"replies":[{"embeddable":true,"href":"https:\/\/kenscourses.com\/tc101winter2016\/wp-json\/wp\/v2\/comments?post=34833"}],"version-history":[{"count":2,"href":"https:\/\/kenscourses.com\/tc101winter2016\/wp-json\/wp\/v2\/posts\/34833\/revisions"}],"predecessor-version":[{"id":34870,"href":"https:\/\/kenscourses.com\/tc101winter2016\/wp-json\/wp\/v2\/posts\/34833\/revisions\/34870"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/kenscourses.com\/tc101winter2016\/wp-json\/wp\/v2\/media\/34864"}],"wp:attachment":[{"href":"https:\/\/kenscourses.com\/tc101winter2016\/wp-json\/wp\/v2\/media?parent=34833"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/kenscourses.com\/tc101winter2016\/wp-json\/wp\/v2\/categories?post=34833"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/kenscourses.com\/tc101winter2016\/wp-json\/wp\/v2\/tags?post=34833"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}