--Originally published at The Talking Chalk

The Task

Create a program that determines how many possible lychrel numbers, non lychrel numbers, and palindromes exist between a range.

The Process

For sure this WSQ was the one that made the boat enter from calm waters to the tempest. It was not so complicated, yet it required brains. I even managed to find a video from another Problem Solving Course which helped to give body to my code; however, I still faced problems with the library.

The Code

#include<iostream>
#include<vector>
#include <math.h>
using namespace std;
#include “BigIntegerLibrary.hh”

BigInteger tester(BigInteger number)
{
BigInteger toturn=0;
while(number>0)
{
toturn=(toturn*10)+(number%10);
number=number/10;
}
return toturn;
}
BigInteger lychrels(BigInteger number)
{
BigInteger sumnums, toret, counter=0;
if(number==tester(number))
{
toret=1;
}
else
{
sumnums=number+tester(number);
while(counter!=30 && sumnums != tester(sumnums))
{
if (counter >=30)
{
toret=2;
cout<<“Lychrel number candidates.”<<number<<endl;
}
else
{
toret=3;
}
}
}
return toret;
}
int main()
{
BigInteger lowest, highest, lychrel=0, palindromes=0, toret, nonlyc=0, number;
cin>>lowest;
cin>>highest;
number=lowest;
for(int counter=0; number<highest; counter++)
{
number+=counter;
if(lychrels(number)==1)
{
palindromes++;
}
else if (lychrels(number)==2)
{
lychrel++;
}
else
{
nonlyc++;
}
}
cout<<“lychrels “<<lychrel<<endl;
cout<<“natural palindrome “<<palindromes<<endl;
cout<<“non-lychrel “<<nonlyc<<endl;
return 0;
}

The topics

#Basic types and their use

--Originally published at The Talking Chalk

The Task

Create a program with a function that returns the factorial of the number given in the parameter.

The Process

The Code

#include <iostream>
#include <math.h>
using namespace std;

int main()
{
float number[10], sum, average, variance, sdev;
cout<<“Give ten numbers.”<<endl;
for(int counter = 0; counter<10; counter++)
{
cin>>number[counter];
sum+=number[counter];
average=sum/10;
variance+=pow(number[counter]-average, 2)/10;
sdev=sqrt(variance);
}
cout<<“The sum of the given numbers is: “<<sum<<endl;
cout<<“The average of the given numbers is: “<<average<<endl;
cout<<“The standard deviation of the given numbers is: “<<sdev<<endl;
return 0;
}

The topics

#For

#Arrays/vectors

--Originally published at The Talking Chalk

The Task

Create a program with a function that returns the factorial of the number given in the parameter.

The Process

The Code

#include <iostream>
using namespace std;

int factorial (int num)
{
int counter=1, factorial=num;//set a counter, set factorial as the given number
do
{
factorial*=counter; //multiply factorial per all the numbers counter can have that are smaller than num
counter+=1;
}
while(counter<num);//Do while counter is smaller than um
return factorial;
}

int main()
{
cout<<factorial(5)<<endl;
return 0;
}

The topics

#While and do while

--Originally published at The Talking Chalk

The Task

Create a program that asks for two integer values and passes them to functions that return their sum, substractions, multiplication, division and remainder.

The Process

The Code

#include <iostream>
using namespace std;

int sum(int first, int second)
{
return first + second;
}
int subst(int first, int second)
{
return first – second;
}
int mult(int first, int second)
{
return first * second;
}
int div(int first, int second)
{
return first / second;
}
int rem(int first, int second)
{
return first % second;
}
int main()
{
cout<<sum(6,9)<<endl<<subst(6,9)<<endl<<mult(6,9)<<endl<<div(6,9)<<endl<<rem(6,9)<<endl;
return 0;
}

The topics

#Calling functions

#Creating functions

--Originally published at The Talking Chalk

The Task

Create a program that asks for two integer values and prints the sum of all integer numbers between these values.

The Process

The Code

#include <iostream>
using namespace std;

int main ()
{
int big, low, sum=0;
cout<<“Give a number”<<endl;
cin>>low; //User gives value for low
cout<<“Now give a bigger number”<<endl;
cin>>big; //User gives value for big

do
{
low=low+1; //Sums 1 to low, so this low is a number between the original low and big
sum+=low; //Sums the value of low to sum
}
while(low<big); //the process repeats until low is equal to big, so sum will be the sum of all number between low and big
cout<<“The sum of the numbers between the two given is equal to “<<sum<<endl;
return 0;
}

The topics

#Basic output

#Basic input