Create a program that asks the user for a non-negative integer (let’s call that number n) and display for them the value of n! (n factorial).

After showing them the answer, ask them if they would like to try another number (with a simple y/n response) and either ask again (for y) or quit the program and wish them a nice day (if they answered n).

This where my instructions. And this is how I what I did.

This program accepts a “n” positive number and multiplies it in a sequence for example: 5!=102, this is also 1 x 2 x 3 x 4 x 5=120.

Also this program has a loop that ends with the sequence of the multiplications.

//CODE:

#include <iostream>
using namespace std;

int main(int argc, char const *argv[]) {
int n, n2, conta;
char ans;
std::cout << “This program prints the factorial of <n> number.” << std::endl;
do {
std::cout << “Please enter a non-negative number to calculate the factorial.” << std::endl;
std::cin >> n;
if (n==0) {
std::cout << “The factorial is… 1” << std::endl; //cuando corro el programa sale factorial is… 1 y después factorial is… 0 y despues vulve a preguntar….
}
conta=n;
do {
conta=conta-1;
n=n*conta;
} while(conta !=1);
std::cout << “The factorial is… “<<n << std::endl;
std::cout << “Do you like to add another factorial? Write <y> for yes and <n< for no” << std::endl;
std::cin >> ans;

} while(ans==’y’);

return 0;
}

Hey world…

In this WSQ I had to go back to the WSQ03 and yes is the same but the difference with this one, is that now the code has functions out of the “main” and I learnt how to create th synthesis of a function in C++.

You will go back and do WSQ03 – Fun with Numbers again.

But this time, write a function for each calculation. Each function should define two parameters (in this example of type int) and return the correct value as an integer as well.

You main program needs to ask the user for the input and then call each function to calculate.

//CODE:

#include <iostream>
using namespace std;

int difference(int a, int b) {
return(a-b);
}
int product(int a, int b) {
return(a*b);
}
int integerdiv(int a, int b) {
return((int)(a/b));
}
int residue(int a, int b) {
return(a%b);
}

int main(int argc, char const *argv[]) {
int x, y, d, p, i, r;

std::cout << “This program is similar to WSQ03, but now with functions.” << std::endl;
std::cout << “Please enter number 1.” << std::endl;
std::cin >> x;
std::cout << “Please enter number 2.” << std::endl;
std::cin >> y;
d=difference(x, y);
p=product(x, y);
i=integerdiv(x, y);
r=residue(x, y);
std::cout << “The difference is… “<<d << std::endl;
std::cout << “The product is… “<<p << std::endl;
std::cout << “The integer division is… “<<i << std::endl;
std::cout << “The residue is… “<<r << std::endl;
return 0;
}

This are all the functions I created.

And this is how they are called into the “main”.

This code was easy as I remember!! Also just a little of research in formulas to be able to complete it.

I wrote a program that asks for a range of integers and then prints the sum of the numbers in that range (inclusive).

I did use a formula to calculate this of course but what we want you to do here is practice using a loop to do repetitive work.

x=(n*(n+1))/2;

For example, the sum from 6 to 10 would be 0 + 6 + 7 + 8 + 9 + 10.

//CODE:

#include <iostream>

using namespace std;

void sumofnumbers(int n) {
int R=0;
R=(n*(n+1))/2;
std::cout << “The sum of the range is… “<<R << std::endl;
}

int main(int argc, char const *argv[]) {
int n, R;
std::cout << “This program sum the rage of numbers from the enter one.” << std::endl;
std::cout << “Please enter a number to sum its range.” << std::endl;
std::cin >> n;
sumofnumbers(n);

return 0;
}

This one was a little tricky, because I had to do some research of certain commands for it to properly run…

I made a program that picks a random integer in the range of 1 to 100.

It then prompts the user for a guess of the value, with hints of ’too high’ or ’too low’ from the program.

Hey guys since I have already told you I am catching up!!…

What I had to do for this #WSQ05 well is simple… I made a program that will prompt the user for a temperature in Fahrenheit and then convert it to Celsius. You may recall that the formula is C = 5 ∗ (F − 32)/9.

Modify the program to state whether or not water would boil at the temperature given.

This is what i did…//Code starts from next line

//CODE

#include <iostream>
using namespace std;

int main(int argc, char const *argv[]) {
float fa;
int cel;

std::cout << “This program can determine the temperature from Farenheit to Celcius.” << std::endl;
std::cout << “Please enter the temperature in ºFarenheit.” << std::endl;
std::cin >> fa;
cel=(int)5*(fa-32)/9;
std::cout << “The temperature given in ºCelcius is… “<<cel << std::endl;
if (cel>100) {
std::cout << “The water can boil at this temperature at typical conditions… Be careful!” << std::endl;
}
else{
std::cout << “The water does not boil at this temperature.” << std::endl;
}
return 0;
}