--Originally published at Quirino´s Projects

Made a TicTacToe in python

NOTE: I do not recomend using this code since indenting in wordpress is a hard task, instead, download it from my GitHub repo;

https://github.com/QuirinoC/TicTacToe.py

'''
Juan Carlos Quirino Carrasco
-----------------------------------------------------
Tried to do all functions as simple as possible
Maybe later i will do a more beautiful change_turn(),
user_input() and win(),tie()
-----------------------------------------------------
You are free to user, change and everything, just dont
copy and present like yours, you can, but give credit
'''
def table():
#this function creates a 3x3 table
'''
- / - / -
- / - / -
- / - / -
'''
board = []
for i in range(3):
board.append(["-"]*3)
return board
def print_board(board):
'''This function prints the board in pretty formated way'''
for column in board:
print ()
for i in column:
print (i, end=" ")
print ("\n")
'''
This is incorrect since it would
print the same column 3 times
'''
#print (" ", board_[i] , end=" / ")
#print (board_[i] , end=" / ")
#print (board_[i])
#print()
def win(board):
global turn
'''
This function checks if someone wins
Must be called every time someone writes
'''
a = board[0][0]
b = board[0][1]
c = board[0][2]
d = board[1][0]
e = board[1][1]
f = board[1][2]
g = board[2][0]
h = board[2][1]
i = board[2][2]
#Add to test for not being '-' DONE
''' 0 1 2
0 a / b / c
1 d / e / f
2 g / h / i
'''
if \
(a == b and b == c and b != "-") or \
(d == e and e == f and e != "-") or \
(g == h and h == i and h != "-") or \
\
(a == d and d == g 

 d != "-") or \
(b == e and e == h and e != "-") or \
(c == f and f == i and f != "-") or \
\
(a == e and e == i and e != "-") or \
(c == e and e == g and e != "-"):
if turn == 1:
turn = 2
else:
turn = 1
print ("\n\n\n\n\n\n\n\n\n\n\n\n\n\nPlayer {} wins!".format(turn))
return False
return True
def tie(board):
a = board[0][0]
b = board[0][1]
c = board[0][2]
d = board[1][0]
e = board[1][1]
f = board[1][2]
g = board[2][0]
h = board[2][1]
i = board[2][2]
if a != "-" and b != "-" and c != "-" and \
d != "-" and e != "-" and f != "-" and \
g != "-" and h != "-" and i != "-":
return True
return False
def change_turn():
global turn
global OXturn
print_board(board)
if turn == 1:
turn = 2
OXturn = "O"
else:
turn = 1
OXturn = "X"
def user_input():
#
global turn
#
valid_inputs = ['Q','W','E',
'A','S','D',
'Z','X','C']
#
u_input = input("Its player {} turn [] ... ".format(turn)).upper()
if u_input in valid_inputs:
if u_input == "Q" and board[0][0] == "-":
board[0][0] = OXturn
change_turn()
elif u_input == "W" and board[0][1] == "-":
board[0][1] = OXturn
change_turn()
elif u_input == "E" and board[0][2] == "-":
board[0][2] = OXturn
change_turn()
elif u_input == "A" and board[1][0] == "-":
board[1][0] = OXturn
change_turn()
elif u_input == "S" and board[1][1] == "-":
board[1][1] = OXturn
change_turn()
elif u_input == "D" and board[1][2] == "-":
board[1][2] = OXturn
change_turn()
elif u_input == "Z" and board[2][0] == "-":
board[2][0] = OXturn
change_turn()
elif u_input == "X" and board[2][1] == "-":
board[2][1] = OXturn
change_turn()
elif u_input == "C" and board[2][2] == "-":
board[2][2] = OXturn
change_turn()
else:
print ("Please give a valid input")
user_input()
''' 0 1 2
0 q / w / e
1 a / s / d
2 z / x / c
'''
def instructions():
print ("\n\n\n\n\n\n\n\n\n\n\n\n\nThis is a tictactoe game to play just type in your keyboard as described\n")
print ("q / w / e")
print ("a / s / d")
print ("z / x / c")
def game():
instructions()
while win(board):
user_input()
if tie(board):
print_board(board)
if input("Its a tie\nWanna play again?(Y/N)").lower() == "n":
break
print_board(board)

board = table()
input_board = table()
turn = 1
OXturn = "X"
game()